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2e3d01ae0bTechnically there appear to also be a two and many... but this at least
removes some of the bug.
```
def wrong(n)
n != 13 || n != 14
end
def right(n)
n != 13 && n != 14
end
[13, 14, 15].each do |n|
puts "#{n}: wrong=#{wrong(n)}, right=#{right(n)}"
end
```
15 is (not 13) OR (not 14)
15 is not (not 13) AND (not 14)
apologies for the headache.
39 lines
1.4 KiB
Ruby
Vendored
39 lines
1.4 KiB
Ruby
Vendored
# frozen_string_literal: true
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RSpec.describe "Breton plural rules", type: :integration do # rubocop:disable RSpec/DescribeClass
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let(:br_plural_rule) do
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plurals = eval(File.read(Rails.root.join("config/locales/plurals.rb"))) # rubocop:disable Security/Eval
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plurals[:br][:i18n][:plural][:rule]
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end
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# Per CLDR: https://unicode.org/cldr/charts/45/supplemental/language_plural_rules.html
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# few: n % 10 = 3..4,9 and n % 100 != 10..19,70..79,90..99
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describe ":few category" do
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it "returns :few for n % 10 in 3,4,9 when n % 100 not in excluded ranges" do
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[3, 4, 9, 23, 24, 29, 43, 44, 49, 103, 104, 109].each do |n|
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expect(br_plural_rule.call(n)).to eq(:few), "Expected #{n} to be :few"
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end
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end
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it "returns :other for n % 10 in 3,4,9 when n % 100 IS in 10..19" do
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[13, 14, 19].each do |n|
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expect(br_plural_rule.call(n)).to eq(:other),
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"Expected #{n} to be :other (n % 100 in 10..19)"
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end
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end
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it "returns :other for n % 10 in 3,4,9 when n % 100 IS in 70..79" do
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[73, 74, 79].each do |n|
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expect(br_plural_rule.call(n)).to eq(:other),
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"Expected #{n} to be :other (n % 100 in 70..79)"
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end
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end
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it "returns :other for n % 10 in 3,4,9 when n % 100 IS in 90..99" do
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[93, 94, 99].each do |n|
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expect(br_plural_rule.call(n)).to eq(:other),
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"Expected #{n} to be :other (n % 100 in 90..99)"
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end
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end
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end
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end
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